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Find the acceleration of a car that comes to a stop from a velocity of 60 m/s in a distance of 360 m.​

Sagot :

Answer:

Initial velocity of car = 60 m/s = u

Final velocity = 0 = v

Distance covered  = 360 m = S

Acceleration (or in this case deceleration) = a

v^2 - u^2 = 2aS

0 - (60) = 2a x 360

-3600 = 720a

-3600/720 = a

therefore, a = -5 m/s^2

Therefore the deceleration of the car is -5 m/s^2.