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x4 - 7x2 + 12 = 0solving equation transfer to quadratic equation ​

Sagot :

Answer:

the x values are 2, -2, √3, -√3.

Step-by-step explanation:

first let x^2 = y

then the equation will be

y^2-7y+12=0

factor out the equation

(y-4)(y-3)=0

use zero product property

y=4, y=3

then go back to the first equation

let x^2 = y

√x^2 = √ 4

x = +- 2

√x^2 = +- √3

the x values are 2, -2, √3, -√3.