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a woman applying a force of 100 N on a lawnmower. The lawnmower has moved a distance of 3.5 m. The handle of the lawnmower makes a 30° anglewith the horizontal.how much work was done?​

Sagot :

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The work done by an object exerting a force F at an angle θ and at a distance d is given by

[tex]\boxed{W = Fd \: \cos \theta}[/tex]

where:

W = work

F = force

d = distance

θ = angle of the force with the horizontal

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for W

W = Fd cos θ

W = (100 N)(3.5 m)(cos 30°)

[tex]\boxed{W = \text{303.11 J}}[/tex]

Therefore, the work done is 303.11 J.

[tex]\\[/tex]

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