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Help po please :'(

• -6x+3=2x² in standard form

• 2x²-x+-1 in standard form

• 2ײ=9 in standard form ​


Sagot :

1.) 2ײ + 6x-1 = 0

2.) y = 2ײ - 4× + 2

3.) x = (√72) (ilagay sa baba ng 72 yung 4)


Answer and step-by-step explanation:

The given equations are all quadratic equations so let's use the standard form of a quadratic equation:

ax^2 + bx + c = 0

1. Subtract 2x^2 to both sides of the equation to equate the equation to 0. Then arrange the terms from the highest degree to the lowest degree.

-6x + 3 = 2x^2

-6x + 3 - 2x^2 = 2x^2 - 2x^2

Standard form: -2x^2 - 6x + 3 = 0

2. Remove the plus sign after x and equate the equation to 0.

2x^2 - x + - 1

Standard form: 2x^2 - x - 1 = 0

3. Subtract 9 to both sides of the equation to equate the equation to 0.

2x^2 = 9

2x^2 - 9 = 9 - 9

Standard form: 2x^2 - 9 = 0

*Note: This sign (^) means the number after it is an exponent.