Marygraceboraleidn
Answered

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(x²+y²-2xy)-(x²-y²-2xy)

a. x - y - 2xy
b. y - 2xy
c. 2y^2
d. 2x^2​

Sagot :

Luzvismindamagbanua9idn

Answer:

c. 2y^2

Step-by-step explanation:

(x²+y²-2xy)-(x²-y²-2xy)

= x²+y²-2xy-x²+y²+2xy

combine like terms

= 2y²

Pathologistidn

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Question:

(x²+y²-2xy)-(x²-y²-2xy)

a. x - y - 2xy

b. y - 2xy

c. 2y^2

d. 2x^2​

Answer:

[tex](x^{2} + y ^{2} - 2xy) - (x^{2} - y ^{2} - 2xy)[/tex]

  • Remove unnecessary parentheses

[tex]x^{2} + y ^{2} - 2xy - (x^{2} - y ^{2} - 2xy)[/tex]

  • When there is a - in front of an expression in parentheses, change the sign of each term in the expression

[tex](x^{2} + y ^{2} - 2xy) - (x^{2} + y ^{2} + 2xy)[/tex]

  • Since two opposites add up to zero, remove them from the expression

[tex]y^{2} + y^{2}[/tex]

  • if a term doesn't have a coefficient, it is considered that the coefficient is 1

[tex]1y^{2} + y^{2}[/tex]

  • if a term doesn't have a coefficient, it is considered that the coefficient is 1

[tex]1y^{2} + 1y^{2}[/tex]

  • Collect like terms by adding their coefficients

[tex]\\ (1+1)y^{2}[/tex]

  • Add the numbers

[tex]2y^{2}[/tex]

The Final Answer is:

(x²+y²-2xy)-(x²-y²-2xy)

a. x - y - 2xy

b. y - 2xy

c. 2y^2

d. 2x^2​

The answer is: C. 2y^2

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