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find the solution of the following quadratic equation x squared minus 4x + 4 = 0​

Sagot :

✏️QUADRATIC

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[tex] \large \bold{\blue{PROBLEM:}} [/tex] find the solution of the following quadratic equation x squared minus 4x + 4 = 0.

  • [tex] x^2 - 4x + 4 = 0 [/tex]

[tex] \large \bold{\blue{SOLUTION:}} [/tex] The quadratic equation is already in standard form. Find the values of a, b, and c.

  • [tex] \boxed{ax^2 + bx + c = 0} [/tex]

  • [tex] a = 1, \: b = \text-4, \: c = 4 [/tex]

» Substitute the values to the quadratic formula to determine solutions.

  • [tex] \boxed{x = \frac{\text-b \pm \sqrt{b^2 - 4ac}}{2a}} [/tex]

  • [tex] x = \frac{\text-(\text-4) \pm \sqrt{(\text-4)^2 - 4(1)(4)}}{2(1)} \\ [/tex]

  • [tex] x = \frac{\text-(\text-4) \pm \sqrt{16 - 4(1)(4)}}{2(1)} \\ [/tex]

  • [tex] x = \frac{4 \pm \sqrt{16 - 16}}{2} \\ [/tex]

  • [tex] x = \frac{4 \pm \sqrt{0}}{2} \\ [/tex]

» Since the discriminant (b² - 4ac) is equal to zero, then there will be one solution for this equation.

  • [tex] x = \frac{4}{2} \\ [/tex]

  • [tex] x = 2 [/tex]

[tex] \large \therefore \underline{\boxed{\tt \purple{x = 2}}} [/tex]

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✏️ANSWER

  • X = 2

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✏️Solution

X² - 4x + 4 = 0

(X - 2)² = 0

X - 2 = 0

X = 2

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Step By Step Explanation:

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Step 1:

  • Factor the expression using a² + 2ab + b² = (a + b)²
  • X² - 4x + 4 = 0

Step 2:

  • The exponential term is zero if and only if the base is zero.
  • (X - 2)² = 0

Step 3:

  • Rearrange unknown term to the left side of the equation.
  • X - 2 = 0

FINAL ANSWER:

  • X = 2