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positive integers from 1 to 365​

Sagot :

Answer:

66795

Step-by-step explanation:

We can consider the series as an A.P (arithmetic progression) with a common difference(d) = 1 , first term (a) = 1 and last term = 365.

So the sum of n terms of the A.P is given by

S(n) = n/2( 2a + (n-1)d ).

or if we are provided with the first term and the last term then we can easily get the sum by

S(n) = n/2( a + L ) “ L = last term “

So putting the values

S = 365/2 ( 1 + 365)

= 365/2 (366)

=66795

Ans : 66795