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A 70 N is applied to an 2070kg truck. If the truck encounters 20 N
frictional force, find its acceleration. *


Sagot :

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The force acting on an object is given by

[tex]\boxed{F_{net} = ma}[/tex]

where:

F net = net force

m = mass

a = acceleration

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for Fnet

F net = F applied - F friction

F net = 70 N - 20 N

F net = 50 N

Solving for a

F = ma

[tex]\dfrac{F_{net}}{m} = \dfrac{ma}{m}[/tex]

[tex]a = \dfrac{F_{net}}{m}[/tex]

[tex]a = \dfrac{\text{50 N}}{\text{2,070 kg}}[/tex]

[tex]\boxed{a = \text{0.0242 m/}\text{s}^{2}}[/tex]

Therefore, the acceleration of the truck is 0.0242 m/s².

[tex]\\[/tex]

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