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how did you fing the roots each equation​

Sagot :

Answer:

The roots of any quadratic equation is given by: x = [-b +/- sqrt(-b^2 - 4ac)]/2a. Write down the quadratic in the form of ax^2 + bx + c = 0. If the equation is in the form y = ax^2 + bx +c, simply replace the y with 0. This is done because the roots of the equation are the values where the y axis is equal to 0.

Step-by-step explanation:

do you mean by "find" right? not fing?

My Answer:

Solution :  

x  

= 3 + 2 √ 7 , x

= 3 − 2 √ 7

Explanation:

Comparing with general equation  

a x 2+ b

= 0  x

2 − 6 x − 19 = 0

;  = 1 , b

= − 6 , c

= − 19 . Discriminant  D

= b 2 − 4 ⋅ a ⋅ c

= 36 + 76

= 112

is positive so roots are real.

Quadratic formula for finding roots is

x  =  − b 2 a ± √ b 2 − 4 a c 2  a  or x

= −  6 2 ± √ 112  2  or  x = 3 ± 4 ⋅ √ 7 2  or  x

= 3 ± 2 ⋅ √ 7

=

Solution :  

x = 3 + 2 √ 7 , x = 3 − 2

√ 7