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What is the centripetal force of 950 kg car moving at 10 m/s take a turn around a circle with a radius of 25 m​

Sagot :

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The centripetal force exerted on an object is given by

[tex]\boxed{F_{c} = \frac{mv^{2}}{r}}[/tex]

where:

Fc = centripetal force

m = mass

v = velocity

r = radius

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for Fc

[tex]F_{c} = \dfrac{mv^{2}}{r}[/tex]

[tex]F_{c} = \dfrac{(\text{950 kg})(\text{10 m/s})^{2}}{\text{25 m}}[/tex]

[tex]\boxed{F_{c} = \text{3,800 N}}[/tex]

Therefore, the centripetal force of the car is 3,800 N.

[tex]\\[/tex]

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