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(x+1)^2. First term Second Term Last Term
(x+2)^2. : :
(x+3)^2. : :
(x+y)^2. : :

PLEASE need ko na po nito paki answer naman po salamt THANKS AND GODBLESS :)

Sagot :

(x+1)²
first term = x²
second term = 2x
last term = 1
⇨ (x²+2x+1)

(x+2)²
first term = x²
second term = 4x
last term = 4
⇨ (x²+4x+4)

(x+3)²
first term = x²
second term = 6x
last term = 9
⇨ (x²+6x+9)

(x+y)²
first term = x²
second term = 2xy
last term = y²
⇨(x²+2xy+y²)

you can also use the foil method
ex) (x+1)² = (x+1)(x+1)
f = the first term (x)(x) = x²
o = outer term (x)(1) = x
i = inner term (1)(x) = x
l = last term (1)(1) = 1
copy the first term, add the outer and inner term and copy also the last term so the answer is (x²+2x+1)

hope you understand my explanations.. i'm not good in explaining because i'm not a teacher..(^_^) AMEN AND GODBLESS YOU TOO AND YOUR FAMILY..
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