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[tex]2x + 4 = \\ x ^{2} + 2x = \\ 4x ^{2} + 8x = \\ x^{2} + 2x + 1 = \\ x^{2} + 5x + 6 = [/tex]
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Sagot :

Gabrielcuyaidn

Answer:

1) 2x²+4= x=0 and x=0

2) x²+2x= x=0 and x=-2

3) 4x²+8x= x=0 and x=-2

4) x²+2x+1= x=-1 and x=-1

5) x²+5x+6= x=-2 and x=-3

Solution:

#USING ANY METHOD OF A QUADRATIC EQUATION

#USING QUADRATIC FORMULA

1)

2x+4

a=0 b=2 c=4

x=-b±√b²-4ac/2a

x=-2±√(2)²-4(0)(4)/2(0)

x=-2±√(4)-0/0

x=-2±√4/0

x=-2±2/0

x=-2+2/0

x=0/0

x=0

x=-2-2/0

x=-4/0

x=0

#The roots of 2x+4 are 0 and 0#

#USING QUADRATIC FORMULA

2)

x²+2x

a=1  b=2  c=0

x=-b±√b²-4ac/2a

x=-2±√(2)²-4(1)(0)/2(1)

x=-2±√(4)-0)/2

x=-2±√4/2

x=-2±2/2

x=-2+2/2

x=0/2

x=0

x=-2-2/2

x=-4/2

x=-2

#The roots of x²+2x are 0 and -2#

#USING QUADRATIC FORMULA

3) 4x²+8x=

a=4  b=8 c=0

x=-b±√b²-4ac/2a

x=-8±√(8)²-4(4)(0)/2(4)

x=-8±√(64-0)/8

x=-8±√64/8

x=-8±8/8

x=-8+8/8

x=0/8

x=0

x=-8-8/8

x=-16/8

x=-2

#The roots of 4x²+8x are 0 and -2#

4)

#USING BY FACTORING

x²+2x+1=

(x+1) (x+1)=0

x²+1x+1x+1=0

x²+2x+1=0

(x+1) (x+1)=0

(x+1)=0 (x+1)=0

x=-1       x=-1

#The roots of x²+2x+1 are -1 and -1#

#USING QUADRATIC FORMULA

x²+2x+1

a=1 b=2 c=1

x=-b±√b²-4ac/2a

x=-2±√(2)²-4(1)(1)/2(1)

x=-2±√(4)-4/2

x=-2±√0/2

x=-2±0/2

x=-2+0/2  

x=-2/2

x=-1

x=-2-0/2

x=-2/2

x=-1

#The roots of x²+2x+1 are -1 and -1#

5)

#USING BY FACTORING

(x+2) (x+3)=0

x²+3x+2x+6=0

x²+5x+6=0

(x+2) (x+3)=0

(x+2)=0  (x+3)=0

x=-2        x=-3

#The roots of x²+5x+6 are -2 and -3#

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