CYPHERSYDNEYidn
Answered

IDNStudy.com, ang komunidad ng pagbabahagi ng kaalaman at mga sagot. Sumali sa aming interactive na platform ng tanong at sagot para sa mabilis at eksaktong tugon mula sa mga propesyonal sa iba't ibang larangan.

A body that starts from rest moves to the right with an acceleration of 4 m/s2.

1. What is its velocity after 3s?
2. What is the distance covered after 3s? 3. What is the velocity of the body after it has travelled 20 m? ​

Sagot :

FierceFireflieeidn

  • initial velocity=u=0m/s
  • Acceleration=a=4m/s^2

Solution:-1

  • Time=t=3s
  • Final velocity=v=?

According to 1st equation of kinematics

[tex]\boxed{\sf v=u+at}[/tex]

[tex]\\ \sf\longmapsto v=0+4(3)[/tex]

[tex]\\ \sf\longmapsto v=12m/s[/tex]

Solution:-2

  • Distance=s=?

According to second equation of kinematics

[tex]\boxed{\sf s=ut+\dfrac{1}{2}at^2}[/tex]

[tex]\\ \sf\longmapsto s=0(3)+\dfrac{1}{2}\times 4\times 3^2[/tex]

[tex]\\ \sf\longmapsto s=2+9[/tex]

[tex]\\ \sf\longmapsto s=11m[/tex]

Solution:-3

  • initial velcity=u=12m/s
  • Distance=s=20m
  • Final velocity=v

According to third equation of kinematics

[tex]\boxed{\sf v^2-u^2=2as}[/tex]

[tex]\\ \sf\longmapsto v^2-(12)^2=2(20)(4)[/tex]

[tex]\\ \sf\longmapsto v^2-144=160[/tex]

[tex]\\ \sf\longmapsto v^2=160+144[/tex]

[tex]\\ \sf\longmapsto v^2=304[/tex]

[tex]\\ \sf\longmapsto v=\sqrt{304}[/tex]

[tex]\\ \sf\longmapsto v=17.3m/s[/tex]

Maraming salamat sa iyong aktibong pakikilahok. Magpatuloy sa pagtatanong at pagbabahagi ng iyong mga ideya. Ang iyong kaalaman ay mahalaga sa ating komunidad. Bumalik ka sa IDNStudy.com para sa maasahang mga sagot sa iyong mga katanungan. Salamat sa iyong tiwala.