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Give me the next 2nd to 5th term of every 5 each Finite Sequence with the common difference of 4. Whose the First term of every 5 each sequence starts with the term of 3, 6, 9, 12, and 15. Prove the problem with significant explanation.

Part 1:


Sagot :

Step-by-step explanation:

Given:

Common Difference "d": 4

First Sequence: A1 = 3

Second Sequence: A1 = 6

Third Sequence: A1 = 9

Fourth Sequence: A1 = 12

Fifth Sequence: A1 = 15

Unknown:

First Sequence: {3, __, __, __, __}

Second Sequence: {6, __, __, __, __}

Third Sequence: {9, __, __, __, __}

Fourth Sequence: {12, __, __, __, __}

Fifth Sequence: {15, __, __, __, __}

-Sequence is a group of terms who has one and the same a common difference to obtain.

Step by step procedure to know the importance:

1.) First Sequence: {3, __, __, __, __}

Solve:

• = 3

• 3 + 4 = 7

• 7 + 4 = 11

• 11 + 4 = 15

• 15 + 4 = 19

Answers: {3 7, 11, 15, 19}

2.) Second Sequence: {6, __, __, __, __}

Solve:

• = 6

• 6 + 4 = 10

• 10 + 4 = 14

• 14 + 4 = 18

• 18 + 4 = 22

Answers: {6, 10, 14, 18, 22}

3.) Third Sequence: {9, __, __, __, __}

Solve:

• = 9

• 9 + 4 = 13

• 13 + 4 = 17

• 17 + 4 = 21

• 21 + 4 = 25

Answers: {9, 13, 17, 21, 25}

4.) Fourth Sequence: {12, __, __, __, __}

Solve:

• = 12

• 12 + 4 = 16

• 16 + 4 = 20

• 20 + 4 = 24

• 24 + 4 = 28

Answers: {12, 16, 20, 24, 28}

5.) Fifth Sequence: {15, __, __, __, __}

Solve:

• = 15

• 15 + 4 = 19

• 19 + 4 = 23

• 23 + 4 = 27

• 27 + 4 = 31

Answers: {15, 19, 23, 27, 31}

Thank you, that's all for these simple explanation.

Do you need Part 2?

For more information about Arithmetic Seqeunce.

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