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2. in which cases can we use the law of sines?
3.Can you site real life application of law of sines?describe how you can apply the law of sines in that situation.give atleast two situations

pasagot po need lang now na po plss


Sagot :

2. The law of sines can be used to compute the remaining sides of a triangle when two angles and a side are known—a technique known as triangulation. It can also be used when two sides and one of the non-enclosed angles are known.

3. Situation 1: You are standing 10 feet away from a certain leaning tower. Find the ladder length that is needed to reach the third floor of the leaning tower if the ladder is placed where you are standing. The angle that is formed by the tower and the ground is 108 degrees, and the angle formed by the tower at the third floor and the ladder will be 20 degrees.

We begin by first drawing out our problem. We draw our triangle and label it with the information that is given.

law of sines

Okay. We see that the side we want to find is the ladder side. We can arbitrarily label that with a. Because we are dealing with any kind of triangle, it doesn't matter which side we label with a, b, or c. If we label the ladder side as a, then our angle A is 108, the angle opposite our side a. We can go ahead and label the 10 as side b. Our angle B is then 20.

Looking at what we have now, we see that we only need the first two parts of our law of sines to find our answer: a/sin A = b/sin B. Plugging in our values, we get a/sin 108 = 10/sin 20. Using algebra to help us solve for a, we get a = (10/sin 20)*sin 108 = 27.8. We have found our answer. The ladder length that is needed is 27.8 feet.

Answer:

2. It can also be used when two sides and one of the non-enclosed angles are known.

  • 3. You can use The Law of sines to solve real-life problems involving oblique triangles..
  • Simply it's state that the ratio of the length of the side of a triangle to the sine of the angle opposite that side is a the same for all sides and angle in a given triangle. In ABC is an oblique triangle with sides A, B and C, then asinA= bsinB=csinC..

Hope it's Help, Pa Brainliest po Thank you :)