Mavicvillamor14idn
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using the same right triangles and activity to find the value of each indicated missing part round off your answer to two decimal places ​

Using The Same Right Triangles And Activity To Find The Value Of Each Indicated Missing Part Round Off Your Answer To Two Decimal Places class=

Sagot :

Jezielsiscon091008idn

TRIGONOMETRY

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#2 - side b?

\begin{gathered} \sf cos \: C = \frac{adjacent}{hypotenuse} \\\end{gathered}

cosC=

hypotenuse

adjacent

\begin{gathered} \sf cos \: C = \frac{b}{10}\\ \end{gathered}

cosC=

10

b

\begin{gathered} \sf cos \: 34° = \frac{b}{10}\\ \end{gathered}

cos34°=

10

b

\sf b = 10(cos \: 34°)b=10(cos34°)

\sf b = 8.29 b=8.29

\large \therefore \: ∴ b = 8.29

\:

#3 - side f?

\begin{gathered} \sf sin \: F = \frac{opposite}{hypotenuse} \\\end{gathered}

sinF=

hypotenuse

opposite

\begin{gathered} \sf sin \: F = \frac{f}{31}\\ \end{gathered}

sinF=

31

f

\begin{gathered} \sf sin \: 43° = \frac{f}{31}\\ \end{gathered}

sin43°=

31

f

\sf f = 31(sin \: 43°) f=31(sin43°)

\sf f = 21.14 f=21.14

\large \therefore \: ∴ f = 21.14

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