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Calculate the final velocity of a car which accelerates from 6.50 m/s² at the distance of 150m

Sagot :

Answer:-

  • Initial velocity=u=0m/s
  • Acceleration=a=6.5m/s^2
  • Distance=s=150m
  • Final velocity=v

According to 3rd equation of kinematics

[tex]\boxed{\sf v^2-u^2=2as}[/tex]

[tex]\sf\longmapsto v^2=2as+u^2[/tex]

[tex]\sf\longmapsto v^2=2(6.5)(150)+(0)^2[/tex]

[tex]\sf\longmapsto v^2=13(450)[/tex]

[tex]\sf\longmapsto v^2=5850[/tex]

[tex]\sf\longmapsto v=\sqrt{5850}[/tex]

[tex]\sf\longmapsto v=76.4m/s[/tex]