Answer:
[tex]1.) \: 7850 \: {cm}^{3} [/tex]
[tex]2.) \: 100 \: {dm}^{3} [/tex]
[tex]3.) \: 113.04 \: {cm}^{3} [/tex]
[tex]4.) \: 565.2 \: {cm}^{3} [/tex]
[tex]5.) \: 14130 \: {cm}^{3} [/tex]
Solution:
[tex]1.) \: volume \: of \: cylinder = \: \pi {r}^{2} h[/tex]
[tex]\pi \: {(10)}^{2} \: (25) \: = \: 100\pi(25) \: = \: 2500\pi \: = \: 7850 \: {cm}^{3} [/tex]
[tex]2.) \: volume \: of \: pyramid = \frac{lwh}{3} \: l = length \: w = width[/tex]
[tex] \frac{5 \times 5 \times 12}{3} = \frac{25 \times 12}{3} = \frac{300}{3} = 100 \: {dm}^{3} [/tex]
[tex]3.) \: volume \: of \: sphere = \frac{4}{3} \pi \: {r}^{3} [/tex]
[tex] \frac{4}{3} \pi {(3)}^{3} = \frac{4}{3} 27\pi = \frac{108}{3} \pi = 36\pi = 113.04 \: {cm}^{3} [/tex]
[tex]4.) \: volume \: of \: cone = \frac{1}{3} \pi \: {r}^{2} h[/tex]
[tex] \frac{1}{3} \pi \: {6}^{2} (15) = \frac{1}{3} \pi \: 36(15) = 12\pi(15) = 180\pi = 565.2 \: {cm}^{3} [/tex]
[tex]5.) \: volume \: of \: sphere = \frac{4}{3} \pi {r}^{3} [/tex]
[tex]d = 2r = 7 \: \frac{30}{2} = 15 = r [/tex]
[tex] \frac{4}{3} \pi {(15)}^{3} [/tex]
[tex] = \frac{4}{3} \pi \: 3375[/tex]
[tex] = \frac{13500}{3} \pi = \: 4500\pi = 14130 \: {cm}^{3} [/tex]
[tex]all \: answer \: are \: calculated \: using[/tex]
[tex]\pi \: = \: 3.14 \: given \: in \: the \: question[/tex]
[tex] \sf{I \: hope \: it \: helps}[/tex]
