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Sagot :

Answer:

Formulas:

T = v sin ∅ ÷ g

Tt = 2t

dy = v² sin² ∅ ÷ 2g

dx = v² sin (2∅) ÷ g

Explaination:

T = (10m/s) sin (30°) ÷ 9.8m/s²

T = 0.51s

Tt = 2 (0.51s)

Tt = 1.02s

dy = (10m/s)² sin² (30°) ÷ 2 (9.8m/s²)

dy = 25m²/s² ÷ 19.6m/s²

dy = 1.27m

dx = (10m/s)² sin (2 30°) ÷ 9.8m/s²

dx = 86.6m²/s² ÷ 9.8m/s²

dx = 8.83m

T = (10m/s) sin (45°) ÷ 9.8m/s²

T = 0.72s

Tt = 2 (0.72s)

Tt = 1.44s

dy = (10m/s)² sin² (45°) ÷ 2 (9.8m/s²)

dy = 50m²/s² ÷ 19.6m/s²

dy = 2.55m

dx = (10m/s)² sin ( 2 45°) ÷ (9.8m/s²)

dx = 100m²/s² ÷ 9.8m/s²

dx = 10.2m

T = (10m/s) sin (50°) ÷ (9.8m/s²)

T = 7.66m/s ÷ 9.8m/s²

T = 0.78s

Tt = 2 (0.78s)

Tt = 1.56s

dy = (10m/s)² sin² (50°) ÷ 2 (9.8m/s²)

dy = 58.68m²/s² ÷ 19.6m/s²

dy = 2.99m

dx = (10m/s)² sin ( 2 50°) ÷ (9.8m/s²)

dx = 98.48m²/s² ÷ 9.8m/s²

dx = 10.04m

T = (10m/s) sin (60°) ÷ (9.8m/s²)

T = 8.66m/s ÷ 9.8m/s²

T = 0.88s

Tt = 2 (0.88s)

Tt = 1.76s

dy = (10m/s)² sin² (60°) ÷ 2 (9.8m/s²)

dy = 74.99m²/s² ÷ 19.6m/s²

dy = 3.82m

dx = (10m/s)² sin (2 60°) ÷ (9.8m/s²)

dx = 86.6m²/s² ÷ 9.8m/s²

dx = 8.83m

Symbolism:

V = initial velocity

T = time ascending

Tt = Total time

dy = height

dx = range