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1. The side of a triangle are 7.6 cm 9.2 cm, and 5.7 cm. Find the perimeter. a 22 cm b. 22.5 cm C. 21.61 cm d. 26.11 cm 2. Using the given in number 1, find the area of the triangle. a. 22 cm b. 22.5 cm? C. 21.61 cm d. 26.11 cm
3. A triangular lot has dimensions 206 yards. 31.4 yards, and 38.3 yards. What is the perimeter of the lot? 3. 30.9 yards b. 89.13 yards c. 98.13 yards d. 90.3 yards 4. How many square yards does the lot covered in problem number 37 a. 323.11 sq, yards b.233.11 sq yards c. 123.33 sq yards d. 321.11 sq yards
5. The cost of the lot per square yards is Php2,500. How much is the value of the triangular lot in problem number3 a. Php807,775 b. Php582,775 c. Php308,325 d. Php802,775​

Sagot :

Answer:

1.b

2.c

3.d

4. a

5. a

Step-by-step explanation:

1. A+B+C = P = 7.6+9.2+5.7 = 22.5cm

2. Semi perimeter = s = 22.5cm/2 = 11.25cm

[tex]\sqrt{s(s-a)(s-b)(s-c)} = \sqrt{11.25(11.25-7.6)(11.25-9.2)(11.25-5.7)} = 21.61cm^{2}[/tex]

3. A+B+C = P = 20.6+31.4+38.3 = 90.3 yards

4.Semi perimeter = s = 90.3 yd/2 = 45.15yd[tex]\sqrt{s(s-a)(s-b)(s-c)} = \sqrt{45.15(45.15-20.6)(45.15-31.4)(45.15-38.3)} = 323.11 yd^{2}[/tex]

5. Cost (Area) = 2500(323.11) = Php 807,775

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