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Answer:
m = 50 kg
t = 3s
vi = 0 m/s
vf = 5 m/s
a. What is the final momentum of the mass?
Formula:
Δp = mΔv
Solution:
Δp = 50 (5 - 0)
Δp = 325
Δp = 300 m/s
The formula Δp = mΔv is the same or can also be written as Δp = m (vf-vi).
b. What is the force acting on the mass?
Formula:
F = Δp / t
Solution:
F = \frac{325}{3}F=
3
325
F = 108.33333...F=108.33333...
F = 100F=100 kg·m/s²
The formula here is derived from Ft = Δp. In order to make the force isolated in the formula, we should divide both sides by time or t.
c. What was the impulse acting on the mass?
Formula:
I = Δp
Solution:
I = 325
I = 300 m/s
Remember, impulse is moving momentum. Therefore, I = Δp is derived from that statement.