Makakuha ng mga sagot mula sa komunidad at mga eksperto sa IDNStudy.com. Tuklasin ang malalim na sagot sa iyong mga tanong mula sa aming komunidad ng mga bihasang propesyonal.

30. In a particular location, from school to James house and to the church formed 120°. The distance from
school to church is 10km while James house to the church is 5 km. In finding the distance between the school
and James house, which of the following is a helpful equation?
school
a=10
church
1200
Jame's house
sinx
sin 120°
sin y
sin 120°
A.
10
C.
---
10
5
5
siny
sinx
sin 120°
В.
5
sin 120°
D.
5
10
10​