Geometric Sequence:
The first term is 3/8.
Solutions:
Given that the second term is 3/4 and fourth term is 3. Then,
a₂ = 3/4
a₄ = 3
a₁ = 3/4/r
a₃ = 3/4r
Using a₄ = 3 and a₃ = 3/4r. Find the common ratio (r).
r = 3/3/4/r
(r)(r) = (3)(4/3)
r² = 12/3
r² = 4
√r² = √4
r = 2
Using r = 2, find the first term of the geometric sequence.
a₁ = a₂/r
a₁ = 3/4/2
a₁ = (3/4)(1/2)
a₁ = 3/8
Find the third term using r = 2 and a₂ = 3/4.
a₃ = (3/4)(2)
a₃ = 6/4
a₃ = 3/2
Keywords: geometric sequence, common ratio
Example of Geometric Sequence: https://brainly.ph/question/1679288
#BetterWithBrainly
