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write in equation form:
the line contains the point (3,5) and is parallel to the line containing (-4,0) and (-1,-2)


Sagot :

Answer:

Since you are given the points of the line then you'll have the slope as:

m = \frac{x_2 - x_1}{y_2-y_1} m=

y

2

−y

1

x

2

−x

1

substituting the points (0,5) and (-5,0)

m = \frac{5-0}{0-(-5)} m=

0−(−5)

5−0

m = 1m=1

substituting the slope and the point(-3,5) you'll have

m = \frac{x_2 - x_1}{y_2-y_1} m=

y

2

−y

1

x

2

−x

1

1 = \frac{x - (-3)}{y - 5}1=

y−5

x−(−3)

y - 5 = x + 3y−5=x+3

y - x = 3 + 5y−x=3+5

y - x = 8y−x=8

or in slope-intercept form

y = x + 8y=x+8

Step-by-step explanation:

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