Marasigansherwin79idn
Answered

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a car accelerates uniformly from 0 to 7.2 m/s in 11.5 seconds what is the acceleration of the car in m/sā€‹

Sagot :

Eunoia98idn

[tex]acceleration = \frac{final \: velocity - starting \: velocity}{elapsed \: time \: } \\ = \frac{7.2 \: m/s - 0 \: m/s}{11.5 \: s} \\= \frac{7.2 \: m/s}{11.5s} \\ = 0.626 \: m/s^{2} [/tex]

#CarryOnLearning

09485825744idn

a) The 2 a is a measure if the rate of change of the velocity within a period of time. Hence

u =

change in velocity

change in time

=

v - u

t

=

72 km/h - 0

11.5 seconds

We now convert 72 km/h into m/s

u = 72 km/h =

72 * 1km

1 hour

1000 m

1 km

1 hour

3600 seconds

= 20 m/s

We now calculate the acceleration a

a = (20 m/s) / (11.5 s) = 1.74 m/s2 (approximetd)