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A water at a gauge pressure of 3.8 atm at street flows into an office building at a speed of 0.60 m/s through a pipe 50 mm in diameter. The pipe tapers down to 2.6 cm in diameter by the top floor, 20 m above. Calculate the flow velocity and the gauge pressure in such a pipe on the top floor. Assume no branch pipe and ignore viscosity.

Sagot :

Let 1 be the position on the street and 2 on the top floor v2 = v1*A1/A2 = 0.78*π*(0.025^2)/(π*(0.014^2)) = 2.49 m/s Now p1 + ρ*g*y1 + 1/2*ρ*v1^2 = p2 + ρ*g*y2 + 1/2*ρ*v2^2 So p2 = p1 + ρ*g*(y1 - y2)...