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Direction;Find the missing parts in each right triangle.


DirectionFind The Missing Parts In Each Right Triangle class=

Sagot :

TRIGONOMETRY

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» For Right Triangle ∆EFG, find:

#1 ; m∠G

  • sin θ = opposite/hypothenuse
  • sin G = 5/9
  • G = sin^(-1) (5/9)
  • G = 33.75°

ANSWER: mG = 33.75°

[tex] \: [/tex]

#2 ; m∠E

  • cos θ = adjacent/hypothenuse
  • cos E = 5/9
  • E = cos^(-1) (5/9)
  • E = 56.25°

ANSWER: m∠E = 56.25°

[tex] \: [/tex]

#3 ; length of G'F

  • (EF)² + (G'F)² = (EG)²
  • 5² + (G'F)² = 9²
  • 25 + (G'F)² = 81
  • (G'F)² = 81 - 25
  • (G'F)² = 56
  • G'F = 7.48

ANSWER: G'F = 7.48

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» For right triangle ∆BCD, find:

#4 ; m∠B

  • sin θ = opposite/hypothenuse
  • sin B = 11/18
  • B = sin^(-1) (11/18)
  • B = 37.67°

ANSWER: m∠B = 37.67°

[tex] \: [/tex]

#5 ; m∠D

  • cos θ = adjacent/hypothenuse
  • cos D = 11/18
  • D = cos^(-1) (11/18)
  • D = 52.33°

ANSWER: m∠D = 52.33°

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