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Step 1: Calculate the molar mass of Al₂O₃.
The molar masses of Al and O are 26.982 g and 15.999 g, respectively.
[tex]\begin{aligned} \text{molar mass} & = \text{2(26.982 g) + 3(15.999 g)} \\ & = \text{102.0 g} \end{aligned}[/tex]
Step 2: Calculate the number of atoms of aluminum by using dimensional analysis.
In 1 mole of Al₂O₃, there are 2 moles of Al.
In 1 mole of Al, there are 6.022 × 10²³ Al atoms.
[tex]\begin{aligned} \text{number of Al atoms} & = \text{3.50 g} \: \text{Al}_2\text{O}_3 \times \frac{\text{1 mol} \: \text{Al}_2\text{O}_3}{\text{102.0 g} \: \text{Al}_2\text{O}_3} \times \frac{\text{2 mol Al}}{\text{1 mol} \: \text{Al}_2\text{O}_3} \times \frac{6.022 \times 10^{23} \: \text{Al atoms}}{\text{1 mol Al}} \\ & = \boxed{4.13 \times 10^{22} \: \text{atoms}} \end{aligned}[/tex]
Hence, there are 4.13 × 10²² aluminum atoms present in 3.50 grams of Al₂O₃.
[tex]\\[/tex]
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