Dar0077idn
Answered

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A bag contains 3 blue, 4 red,2 white and 1 green marbles. You draw out a marble without looking in the bag. What is the probability that you will not draw a red marble?

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Sagot :

Lamawlamaw69idn

Answer:

6/10 or 3/5

Step-by-step explanation:

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Btsarmyhoneyjhaneidn

Answer:

There are a total of 3+4+2=9 marbles in the bag

Step-by-step explanation:

All of the outcomes must add up to 1 . Therefore, the probability of NOT drawing a red marble is the same as one minus the probability of drawing a red marble:

P(Not red) = 1 - P(red)

P(Not red) = 1 - P(red)Since there are a 3 marbles:

P(Not red) = 1 - 3/9 = 6/9 = 2/3

So the probability of Not drawing a red marble is 2/3

An alternative approach would be to see that:

P(red) + P(white) + P(blue) = 1

P(red) + P(white) + P(blue) = 1P(white) + P(blue) = 1 - P(red)

Therefore:

P(Not red) = 1 - P(red) = P(white) = P(blue)