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Sagot :
1. Find speed when, distance is 142 km and time is 2 hours.
Given :
- distance = 142km
- time = 2 hours
- speed = ?
Solution :
[tex]\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{l}\sf speed = \frac{distance}{time} \\ \\ \sf speed = \frac{142}{2} \\ \\ \boxed{\sf speed = 71\: km/h}\end{array}}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}[/tex]
2. A cyclist covers 950 m in 5 minutes. Find his speed in km/hour.
Given :
- distance = 950
- time = 5 minutes
- speed = ?
Solution :
[tex]\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{l}\sf speed = \frac{distance}{time} \\ \\ \sf speed = \frac{0.95}{5} \\ \\ \sf speed = 0.19\: km/h \\ \\ \sf speed = 0.19 × 60 \\ \\ \boxed{\sf speed = 11.4\: km/h}\end{array}}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}[/tex]
3. The car moves 9 km/h, how far it can go after running for about 6 hours?
Given :
- distance = 9 km/h
- time = 6 hours
- speed = ?
Solution :
[tex]\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{l}\sf speed = \frac{distance}{time} \\ \\ \sf speed = \frac{9}{6} \\ \\ \boxed{\sf speed = 1.5\: km/h}\end{array}}\end{gathered} \end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}[/tex]
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