IDNStudy.com, kung saan nagtatagpo ang mga eksperto para sagutin ang iyong mga tanong. Ang aming komunidad ay nagbibigay ng eksaktong sagot upang matulungan kang maunawaan at malutas ang anumang problema.

A. Boyle's law

formula: P1V2=P2V2

1. a gas occupies 12.3 liters at a pressure of 20.0 mmHg what is the valume when the pressure increased to 50.0 mmHg?

2. If a gas at 25.0 °C occupies 3.60 liters at a pressure of 2.00 atm, what will be it's volume at a pressure of 3.50 atm?

B. Charlie's law

formula:
V1 V2
— = —
T1 T2

1. 600.0 mL of air is at 15.0 °C. what is the volume at 50.0 °C?

2. A gas occupies 900.0 mL at a temperature of 32.0 °C. what is the volume at 112.0 °C?​


Sagot :

Answer:

A

1. 4.92L

given:

P1 = 12.3 liters

P2 = 20.0 mmHg

V1 =50.0 mmHg

V2 = ?

Equation: V2=P1V1/P2

=12.3 L(20.0mmHg)/50.0mmHg

=246L/50.0

= 4.92L

Repeat the process on number 2 since V2 rin ang hinahanap.

B.

(ilalagay ko nalang yung gagamitin na equation

1. V2=V1×T2/T1

2. V2=V1×T2/T1