TabalanzaYunaidn
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1. My grandmother was hospitalized at the Community Hospital due to difficulty in
breathing. The nurse supported her breathing with the aid of oxygen gas. The
nurse noted that the tank of oxygen gas has a volume of 14.0L and a pressure of 1
atm. Find the volume of the oxygen when its pressure is changed to 1.2 atm while
the temperature is held constant.
Given: V1=14.0 L, P= 1.0 atm, P2- 1.2 atm
2. The owner of Molina's Toy Balloon at Public Market has a 200.0 L Helium gas at
a temperature of 28°C and a pressure of 760 mmHg and transferred to a tank with
a volume of 68.0 L. What is the internal pressure in atm of the tank if the temperature
is maintained?
Formula: F V - P22 therefore, Pyo Pili
V2
V2
3. A balloon contains 14.0 L of air at a pressure of 760 torr. What will the volume of
the air be when the balloon is taken to a depth of 10 ft in a swimming pool where the
pressure is 981 torr? The temperature of the air does not change.​

Sagot :

Sarrahjadormioidn

Answer:

1. Given: P1 = 1.0 atm, P2 = 1.2 atm, V1 = 14.0 L

To find: V2

Solution:

P1V1 = P2V2

So, V2 = P1V1/P2

V2 = (1)(14)/1.2

V2 = 11.6666 or 11.67 L

Ans: 11.67 L

2. Given: P1 = 760 mmHg/1 atm, V1 = 200.0 L, V2 = 68.0 L

To find: P2

Solution:

Convert mmHg to atm

760 mmHg = 1 atm

P2 = P1V1/V2

P2 = (1)(200.0)/68.0

P2 = 2.94 atm

Ans: 2.94 atm

3. Given: P1 = 760 torr, P2 = 981 torr, V1 = 14.0 L,

To find: V2

Solution:

Convert torr to atm

760 torr = 1 atm

981 torr = 1.29 atm

V2 = V1P1/P2

V2 = (14.0)(1)/1.29

V2 = 10.85 L

Ans: 10.85 L

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