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what is the resistance of an automobile headlight through which 2.50A flows when 12.0V is applied to it?​

Sagot :

Answer:

Apply Ohm’s Law:

U = R x I

Rearranging for R:

R= U / I = 12 / 0.25 = 48 Ohms.

Note that the specification is for maximum operating parameters. Do not increase over them (specially current) or you may damage your bulb.

Was forgetting to calculate the power:

P = U x I = 12 x 0.25 = 3 Watts.

Note: you can remember the equations for Ohm’s Law and Power from voltage and current respectively as Uri and Pui.

Explanation:

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Answer:

Ohm’s Law, formula V=IR

12=.8R

R=12/.8

R=15 Ohms

Explanation: