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A 150 J of energy added to a system that does 50 J of work, by how much will the internal energy of the system be raised?
GIVEN: Q = 150 J (+ since energy was added to the system)
W = 50 J (+ since work is done by the system)
FIND: ∆U = ?
SOLUTION: ∆U = Q - W
= 150 J - (50 J)
∆U = 100 J
FINAL ANSWER: The internal energy of the system raised 100 J.