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calculate the final pressure for 142 ml of a gas measured at 480 torr pressure is allowed to expand to a volume of 200 ml at constant temperature

given
solution and answer ​

Sagot :

Given:

[tex]P_{1} = \text{480 torr}[/tex]

[tex]V_{1} = \text{142 mL}[/tex]

[tex]V_{2} = \text{200 mL}[/tex]

Required:

[tex]P_{2}[/tex]

Strategy:

This is a gas law problem. What gas law should we use?

Since the given quantities are pressure and volume, we will use Boyle's law. According to this gas law, the pressure of a gas is inversely proportional to its volume keeping the amount of gas and its temperature constant.

The formula used for Boyle's law is

[tex]\boxed{P_{1}V_{1} = P_{2}V_{2}}[/tex]

where:

[tex]P_{1} = \text{initial pressure}[/tex]

[tex]V_{1} = \text{initial volume}[/tex]

[tex]P_{2} = \text{final pressure}[/tex]

[tex]V_{2} = \text{final volume}[/tex]

Solution:

Starting with the formula of Boyle's law

[tex]P_{1}V_{1} = P_{2}V_{2}[/tex]

Dividing both sides of the equation by V₂ to solve for P₂

[tex]P_{2} = P_{1} \times \dfrac{V_{1}}{V_{2}}[/tex]

Substituting the given values and solving for P₂

[tex]P_{2} = \text{480 torr} \times \dfrac{\text{142 mL}}{\text{200 mL}}[/tex]

Therefore, the final pressure is

[tex]\boxed{P_{2} = \text{340.8 torr}}[/tex]

Answer:

[tex]P_{2} = \text{340.8 torr}[/tex]

[tex]\\[/tex]

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