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Answer:
If your test statistic is positive, first find the probability that Z is greater than your test statistic (look up your test statistic on the Z-table, find its corresponding probability, and subtract it from one). Then double this result to get the p-value.
A test statistic is a statistic (a quantity derived from the sample) used in statistical hypothesis testing. ... An important property of a test statistic is that its sampling distribution under the null hypothesis must be calculable, either exactly or approximately, which allows p-values to be calculated.
The formula to calculate the test statistic comparing two population means is, Z= ( x - y )/√(σx2/n1 + σy2/n2). In order to calculate the statistic, we must calculate the sample means ( x and y ) and sample standard deviations (σx and σy) for each sample separately.
Explanation:
Answer:
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Explanation:
1. z test
μ= 83
n= 39
σ= 5
x̄ = 85
z = x̄-μ/ σ/ √n
= 85- 83/5/√39
=2.497
2. z test
μ = 8.3
n = 52
σ= 3.17
x̄ = 7.5
z = x̄-μ/ σ/ √n
=7.5-8.3/3.17/√52
= -1.820
3. t test
μ =10
n =9
s= 6.1
x̄ = 15
t = x̄-μ/s/√n
=15-10/6.1/√9
=2.459
4. t test
μ =118.7
n=21
s= 7.18
x̄ = 116.12
t = x̄-μ/s/√n
=116.22-118.7/7.18/√21
= -1.582
5. t test
μ = 219.3
n=22
s= 13.12
x̄ = 215
t = x̄-μ/s/√n
=215-219.3/13.12/√22
= −1.537
6. t test
μ = 15.3
n = 12
s= 2.5
x̄ = 15
t = x̄-μ/s/√n
=15-15.3/2.5/√12
= -0.415
7. z test
μ = 63
n= 43
σ = 4
x̄ = 65
z = x̄-μ/ σ/ √n
=65-63/4/√43
=3.279
8. t test
μ = 23.75
n = 12
s = 4.5
x̄ = 25
t = x̄-μ/s/√n
=25-23.75/4.5/√12
=0.962
9. t test
μ = 108.5
n = 17
s = 4.08
x̄ = 106.22
t = x̄-μ/s/√n
=106.22-108.5/4.08/√17
=-2.304
10. z test
μ = 23.8
n= 42
σ = 2.27
x̄ = 25.5
z = x̄-μ/ σ/ √n
= 25.5-23.8/2.27/√42
=4.853