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A 5.0 kg mass is placed in an elevator that is accelerating upwards at 4.0 m/s2. What is the apparent weight of this mass?

Sagot :

Indrawboyidn

The apparent weight of this mass : 69.05 N

Further explanation

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object

∑F = m. a

F = force, N

m = mass = kg

a = acceleration, m / s²

In elevators there are two possible movements:

  • 1. upward

then the forces that work

N - W = ma

N - mg = ma

N = ma + mg

N = m (a + g) ... equation 1

  • 2. down ward

then the forces that work

w - N = ma

mg - N = ma

N = mg - ma

N = m (g - a) ... equation 2

So the apparent weight :

  • upwards  ⇒ N = m (a + g)
  • downwards ⇒ N = m (g - a)

Known

m = 5.0 kg

a = 4.0 m/s²

The apparent weight :

Because an elevator that is accelerating upwards , then

N = m (a + g)

N = 5 (4 + 9.81)

N = 69.05 N

Learn more  

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