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The measure of the exterior angles of a convex quadrilateral, one at each vertex, are 6x ,4x-10, 4x+10 and 2x+40. Find the measure of each exterior angle.

Sagot :

since it is a quadrilateral, the sum of the interior angles is 360
let the four interior angles be:
A)180-4x-10
B)180-4x+10
C)180-6x
D)180-2x +40

A+B+C+D = 360
180-4x-10+180-4x+10+180-6x+180-2x +40=360
760 - 16x=360
16x = 760-360
16x=400
x=25

Therefore the four exterior angles are
1)4x+10=110
2)4x-10=90
3)6x=150
4) 2x+40=90