Rnkykshmzuidn
Answered

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1. The difference between 10 times a number and 16 is 74. Find the number.

Representation:
Equation:
Solution:
Answer:

2. Find two consecutive odd integers whose sum is 188.

Representation:
Equation:
Solution:
Answer:

3. A mother is twice as old as her daughter. Five years from now, she will be thrice as old as her daughter. How old is the mother 5 years from now?

Representation:
Equation:
Solution:
Answer:

4. Mrs. Co is 45 years old, and her eldest daughter is 21 years old. When will Mrs. Co be 4 less than twice as old as her eldest daughter?

Representation:
Equation:
Solution:
Answer:


Pahelp po pls yung tamang sagot sana bigyan ko 90 pts salamat






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Sagot :

Rararararalphidn

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1. The difference between 10 times a number and 16 is 74. Find the number.

Equation:

10(n) - 16 = 74

Solution:

74 + 16 = 90,

90 ÷ 10 = 9,

n = 9

Answer:

10 (9) - 16 = 74

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3. A mother is twice as old as her daughter. Five years from now, she will be thrice as old as her daughter. How old is the mother 5 years from now?

Equation:

in present: mother's age = dau. age × 2

in 5 years: mother's age = dau. age × 3

Solution:

dau. age = 5

in present: mother's age = 5 × 2 = 10

in 5 years: mother's age = 5 × 3 = 15

Answer:

it's kind of weird, but I think the mother's age 5 years from now is 15.

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4. Mrs. Co is 45 years old, and her eldest daughter is 21 years old. When will Mrs. Co be 4 less than twice as old as her eldest daughter?

Equation:

Mrs. Co = dau. × 2 - 4

Solution:

the difference between Mrs. Co and daughter's age is 24

and let's say: 7 years from now, dau. age = 21 + 7 = 28

so, Mrs. Co = 28 × 2 - 4 = 52

then, Mrs. Co will be 52 in 7 years from now.

checking: 52 - 28 = 24 (the difference between Mrs. Co and dau. age)

Answer:

In 7 years from now, Mrs. Co will be 4 less than twice as old as her eldest daughter.

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this is one of the most challenging set of questions I've encountered

Glad to help

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