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A solution of hydrogen cyanide in water is called hydrocyanic acid or prussic acid.it was discoverd in 1782 by swedish chemist ,Carl Wilhelm Schelle, who prepared it from the pigment prussian blue.Hydrocyanic acid is composed of 3.74% of hydrogen, 44.43% carbon and 51.83% nitrogen. What is its Empirical Formula?​

Sagot :

Solution:

Step 1: Assume that the mass of a compound is 100 g.

[tex]\text{mass H = 3.74 g}[/tex]

[tex]\text{mass C = 44.43 g}[/tex]

[tex]\text{mass N = 51.83 g}[/tex]

Step 2: Calculate the number of moles of each element.

[tex]n \: \text{H = 3.74 g} × \frac{\text{1 mol}}{\text{1.008 g}} = \text{3.7103 mol}[/tex]

[tex]n \: \text{C = 44.43 g} × \frac{\text{1 mol}}{\text{12.01 g}} = \text{3.6994 mol}[/tex]

[tex]n \: \text{N = 51.83 g} × \frac{\text{1 mol}}{\text{14.01 g}} = \text{3.6995 mol}[/tex]

Step 3: Represent an empirical formula.

[tex]\text{empirical formula} = \text{H}_{x}\text{C}_{y}\text{N}_{z}[/tex]

Step 4: Divide the number of moles of each element by the least number of moles.

[tex]x = \frac{\text{3.7103 mol}}{\text{3.6994 mol}} = 1[/tex]

[tex]y = \frac{\text{3.6994 mol}}{\text{3.6994 mol}} = 1[/tex]

[tex]z = \frac{\text{3.6995 mol}}{\text{3.6994 mol}} = 1[/tex]

Step 5: Write the empirical formula.

[tex]\boxed{\text{empirical formula} = \text{HCN}}[/tex]

[tex]\\[/tex]

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