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Answer:
There are 15 ways to choose the first member, 14 ways to choose the second member, 13 for the third member, and 12 for the fourth member.
However, choosing A, then B, then C, then D is the same as choosing D, C, A, B, which is the same as choosing B, C, A, D, etc.
Therefore, we have counted each possible committee 24 times, since there are 4! = 24 ways of rearranging any four committee members.
To account for this, we will divide by 24 so we only count each possible committee once.
15⋅14⋅13⋅1224
=1365 possible committees
Step-by-step explanation: