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what average braking force is necessary to stop 5,000 kg truck with an initial velocity of 100 m/s for 120 seconds?
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Sagot :

Papalitarakoidn

at_answer_text_other

The question does not give any frictional forces like air resistance so we have to assume that these are negligible.

The deceleration, a, of the car can be found using:

v v = u u + 2 a s

where the u is the initial speed of 8.9 m/s and v = o as the car comes to a stop.

The distance, s, it slows down over is 12 m.

So, 0 = u x u + 2 x a x 12

A bit of maths gives:

a = - 3.3 m/ss (the negative sign just tells us that the car is decelerating).

If friction is zero, then the braking force, F, is given by F = ma as this is the only horizontal force acting on the car, which we assume is on a horizontal road:

F = m a

So, F = 800 x - 3.3 = - 2640 N.

(Again the negative sign just tells us that the car is decelerating).

at_explanation_text_other

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