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A figure is made up of three triangles. Each triangle has a base of 6 inches and a height of 4 inches. What is the combined area of all three triangles?
From the given problem, we will first compute only the area of one triangle:
The formula for finding the area of a triangle is as follows:
[tex]\boxed{\rm Area = \dfrac{bh}{2}}[/tex]
where:
Now, we gonna substitute them to their corresponding values.
We have:
After substituting them, we will next evaluate them by the indicated operation.
Solution:
[tex]\begin{aligned}A & = \dfrac{(6)(4)}{2}\\& = \dfrac{24}{2}\\& = \boxed{12\: sq. \: inch.}\end{aligned}[/tex]
Lastly, we will multiply the answer by 3.
[tex]\boxed{12 \: sq. \: inch. \times 3 = 36 \: sq. \: inch.}[/tex]
Answer:
Therefore, the combined area of all (three) triangles is 36 sq. inches.
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