Answered

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The area of a rectangular lot is given by the polynomial 21 x cubed plus 28 x squared minus 14 x. If the length is 7 x, what is the width of the lot?


a.
3 x squared minus 2 x


b.
3 x squared plus 4 x minus 2


c.
3 x squared minus 4 x plus 2


d.
3 x squared plus 4 x plus 2

Sagot :

BinibiningDelidn

Geometry involving Polynomials

The area of a rectangular lot is given by the polynomial 21x³+28x²-14x. If the length is 7x, what is the width of the lot?

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Solution:

The quotient of the area and length represents the width of the rectangle.

[tex]\Large \tt \green{Width = \frac{Area}{Length}}[/tex]

[tex]\large \tt W = \frac{21x^3+28x^2-14x}{7x}[/tex]

[tex] \large \tt W = \frac{7x(3x^2+4x-2)}{7x}[/tex]

[tex]\large \tt W = \frac{\cancel{7x} (3x^2+4x-2)}{\cancel{7x}}[/tex]

[tex]\Large \bold{\purple{W = 3x^2+4x-2}}[/tex]

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Answer:

[tex]\Large \bold{\purple{b. \ \ 3x^2+4x-2}}[/tex]

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