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Determine the number of moles and the number of particles of Na in 25 grams of Na2SO4.

Determine The Number Of Moles And The Number Of Particles Of Na In 25 Grams Of Na2SO4 class=

Sagot :

Given:

mass of Na₂SO₄ = 25.0 g

Required:

moles of Na

number of Na particles

Solution: (moles of Na)

Step 1: Calculate the molar mass of Na₂SO₄.

molar mass of Na₂SO₄ = (22.99 g/mol × 2) + (32.07 g/mol × 1) + (16.00 g/mol × 4)

molar mass of Na₂SO₄ = 142.05 g/mol

Step 2: Calculate the number of moles of Na by using dimensional analysis.

Since there are 2 mol of Na in 1 mol of Na₂SO₄, the number of moles of Na is

[tex]\text{moles of Na = 25.0 g} \: \text{Na}_{2}\text{SO}_{4} × \frac{\text{1 mol} \: \text{Na}_{2}\text{SO}_{4}}{\text{142.05 g} \: \text{Na}_{2}\text{SO}_{4}} × \frac{\text{2 mol Na}}{\text{1 mol} \: \text{Na}_{2}\text{SO}_{4}}[/tex]

[tex]\text{moles of Na = 0.3519887 mol}[/tex]

[tex]\boxed{\text{moles of Na = 0.352 mol}}[/tex]

Solution: (number of Na particles)

[tex]\text{number of Na particles = 0.3519887 mol Na} × \frac{6.022 × 10^{23} \: \text{Na particles}}{\text{1 mol Na}}[/tex]

[tex]\boxed{\text{number of Na particles} = 2.12 × 10^{23} \: \text{particles}}[/tex]

[tex]\\[/tex]

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