Answered

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The diameter of a circle has length 12. The center is at
(−2,5)
. Give the equation of the circle.


Sagot :

[tex] \large\underline \mathcal{{QUESTION:}}[/tex]

The diameter of a circle has length 12. The center is at (−2,5).

[tex]\\[/tex]

[tex] \large\underline \mathcal{{SOLUTION:}}[/tex]

  • Diameter = 12 so Radius = 6

Given that n= -2 , k= 5 , r= 6

[tex]\\[/tex]

Substitute the values to the standard form of a circle:

[tex]\sf{(x-h)^2+(y-k)^2=r^2}[/tex]

[tex]\sf{(x-(-2))^2+(y-5)^2=6^2}[/tex]

[tex]\boxed{\sf{(x+2)^2+(y-5)^2=36}}[/tex]

[tex]\\[/tex]

[tex] \large\underline \mathcal{{ANSWER:}}[/tex]

  • The equation is (x+2)²+(y-5)²=36