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a gas has a volume of 4.00 L at 0 degrees celsius what final temperature in degrees celsius is needed to cause the volume of the gas to change to 2.50 L if n and p are not charged.​

Sagot :

Given:

[tex]V_{1} = \text{4.00 L}[/tex]

[tex]T_{1} = \text{0°C + 273 = 273 K}[/tex]

[tex]V_{2} = \text{2.50 L}[/tex]

Unknown:

[tex]T_{2}[/tex]

Solution:

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]

[tex]T_{2} = T_{1} × \frac{V_{2}}{V_{1}}[/tex]

[tex]T_{2} = \text{273 K} × \frac{\text{2.50 L}}{\text{4.00 L}}[/tex]

[tex]T_{2} = \text{170.6 K}[/tex]

[tex]T_{2} = \text{170.6 K} - 273[/tex]

[tex]\boxed{T_{2} = -\text{102.4°C}}[/tex]

[tex]\\[/tex]

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