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in a box of letters, there are 3x's, 4y's, and 13z's. In a second box, there are
7x's, 15y's, and 2z's. The content of the two boxes are put together in a third
box. What are the final contents of the third box?
Follow the steps in answering the problems.
1. Express the contents of the first box into polynomials.
Express the contents of the second box into polynomials.
2. Formulate an equation.

Show your complete solution vertically or horizontally.

Please help me I'm really bad at mathematics ಠ︵ಠ​


Sagot :

Answer:

Ermmm-

The final box would contain 10x's, 19y's and 15z's.

1.

b1= 3x + 4y + 13z

b2= 7x + 15y + 2z

2.

b3=

3x + 4y + 13z

7x + 15y + 2z

10x + 19y + 15z

Hope it helps.

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