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In the figure, circle O is inscribed in equilateral triangle ABC and X , Y and Z are the points of tangency. If the side of triangle ABC is 12, how long is the radius of circle O. 

full solutions please and thank you :)

In The Figure Circle O Is Inscribed In Equilateral Triangle ABC And X Y And Z Are The Points Of Tangency If The Side Of Triangle ABC Is 12 How Long Is The Radiu class=

Sagot :

VilesXidn
Given:
side = 12

see figure:

a right triangle is formed.

where the hypotenuse is. h - r
and the other sides are r and 12/2

[tex]h= \sqrt{6^2+12^2} [/tex]

h=10.39

to get the radius we use the Pythagorean theorem.

[tex]10.39-r= \sqrt{(r)^2+(6)^2} [/tex]

[tex]r=3.46[/tex]
View image VilesX
AnneCidn
r = 2 √3

See attached for solution. :)
Btw, I used trig functions, because it is the easiest way to solve it. Haha. I hope you're familiar with that.


<XBO is 1/2 of <XBA. That is why it's 30º
View image AnneC
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