IDNStudy.com, ang iyong pangunahing mapagkukunan para sa mga sagot ng eksperto. Sumali sa aming platform ng tanong at sagot upang makakuha ng eksaktong tugon sa lahat ng iyong mahahalagang tanong.
Answer:
Given polynomial is x²-12x+20
Given polynomial is x²-12x+20On comparing with ax²+bx+c then we have
Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20
Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20we know that
Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20we know thatsum of the zeroes =-b/a
Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20we know thatsum of the zeroes =-b/a=>-(-12)/1
Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20we know thatsum of the zeroes =-b/a=>-(-12)/1=>12
Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20we know thatsum of the zeroes =-b/a=>-(-12)/1=>12Sum of the zeroes =12
Step-by-step explanation:
hope it helps
thank you for following me