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what is the sum of the zeros of g(x) =x2 -7x+12

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Answer:

Given polynomial is x²-12x+20

Given polynomial is x²-12x+20On comparing with ax²+bx+c then we have

Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20

Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20we know that

Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20we know thatsum of the zeroes =-b/a

Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20we know thatsum of the zeroes =-b/a=>-(-12)/1

Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20we know thatsum of the zeroes =-b/a=>-(-12)/1=>12

Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20we know thatsum of the zeroes =-b/a=>-(-12)/1=>12Sum of the zeroes =12

Step-by-step explanation:

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